| // Copyright 2012 The Rust Project Developers. See the COPYRIGHT |
| // file at the top-level directory of this distribution and at |
| // http://rust-lang.org/COPYRIGHT. |
| // |
| // Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or |
| // http://www.apache.org/licenses/LICENSE-2.0> or the MIT license |
| // <LICENSE-MIT or http://opensource.org/licenses/MIT>, at your |
| // option. This file may not be copied, modified, or distributed |
| // except according to those terms. |
| |
| // Issue #14893. Tests that casts from vectors don't behave strangely in the |
| // presence of the `_` type shorthand notation. |
| // Update: after a change to the way casts are done, we have more type information |
| // around and so the errors here are no longer exactly the same. |
| |
| struct X { |
| y: [u8; 2], |
| } |
| |
| fn main() { |
| let x1 = X { y: [0, 0] }; |
| |
| // No longer a type mismatch - the `_` can be fully resolved by type inference. |
| let p1: *const u8 = &x1.y as *const _; |
| let t1: *const [u8; 2] = &x1.y as *const _; |
| let h1: *const [u8; 2] = &x1.y as *const [u8; 2]; |
| |
| let mut x1 = X { y: [0, 0] }; |
| |
| // This is still an error since we don't allow casts from &mut [T; n] to *mut T. |
| let p1: *mut u8 = &mut x1.y as *mut _; //~ ERROR casting |
| let t1: *mut [u8; 2] = &mut x1.y as *mut _; |
| let h1: *mut [u8; 2] = &mut x1.y as *mut [u8; 2]; |
| } |
