| // It should not be possible to use the concrete value of a defaulted |
| // associated type in the impl defining it -- otherwise, what happens |
| // if it's overridden? |
| |
| #![feature(specialization)] |
| |
| trait Example { |
| type Output; |
| fn generate(self) -> Self::Output; |
| } |
| |
| impl<T> Example for T { |
| default type Output = Box<T>; |
| default fn generate(self) -> Self::Output { |
| Box::new(self) //~ ERROR mismatched types |
| } |
| } |
| |
| impl Example for bool { |
| type Output = bool; |
| fn generate(self) -> bool { self } |
| } |
| |
| fn trouble<T>(t: T) -> Box<T> { |
| Example::generate(t) //~ ERROR mismatched types |
| } |
| |
| fn weaponize() -> bool { |
| let b: Box<bool> = trouble(true); |
| *b |
| } |
| |
| fn main() { |
| weaponize(); |
| } |