| # Copyright 2023 The Shac Authors |
| # |
| # Licensed under the Apache License, Version 2.0 (the "License"); |
| # you may not use this file except in compliance with the License. |
| # You may obtain a copy of the License at |
| # |
| # http://www.apache.org/licenses/LICENSE-2.0 |
| # |
| # Unless required by applicable law or agreed to in writing, software |
| # distributed under the License is distributed on an "AS IS" BASIS, |
| # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. |
| # See the License for the specific language governing permissions and |
| # limitations under the License. |
| |
| def cb(ctx): |
| if ctx.platform.os == "windows": |
| cmd = ["cmd.exe", "/c", "hello_world.bat"] |
| else: |
| cmd = ["./hello_world.sh"] |
| |
| # Launch more parallel subprocesses than shac will actually allow to run in |
| # parallel, i.e. more than any realistic machine will have cores (but not |
| # too many, or the test will be very slow). |
| num_procs = 1000 |
| procs = [ctx.os.exec(cmd) for _ in range(num_procs)] |
| |
| # It should be possible to wait on the subprocesses in the reverse of the |
| # order in which they were started without causing a deadlock; the lock |
| # should be released asynchronously, not by calling wait(). |
| for proc in reversed(procs): |
| res = proc.wait() |
| print(res.stdout.strip()) |
| |
| shac.register_check(cb) |