//===--- PrefixMap.h - A ternary tree ---------------------------*- C++ -*-===//
//
// This source file is part of the Swift.org open source project
//
// Copyright (c) 2014 - 2017 Apple Inc. and the Swift project authors
// Licensed under Apache License v2.0 with Runtime Library Exception
//
// See https://swift.org/LICENSE.txt for license information
// See https://swift.org/CONTRIBUTORS.txt for the list of Swift project authors
//
//===----------------------------------------------------------------------===//
//
//  This file defines a data structure which stores a map whose keys are
//  sequences of comparable values.  Specifically, it implements the trie
//  variant known as a ternary search tree.  In performance, it is similar
//  to a binary tree; however, it has two properties specific to the use of
//  homogeneous sequences as keys:
// 
//    - Individual entries do not necessarily store the entire key; instead,
//      the key data may be spread over a sequence of nodes.  This causes the
//      tree to be much more space-compact when keys share common prefixes.
//      This does require an extra pointer of storage in each node.
//
//      Unlike some traditional presentations of ternary trees, this
//      implementation allows more than one key element per node.
//
//    - It is efficient to find entries that share a common prefix with
//      a given key.
//
//  FIXME: The current implementation doesn't rebalance siblings.
//
//===----------------------------------------------------------------------===//

#ifndef SWIFT_BASIC_PREFIXMAP_H
#define SWIFT_BASIC_PREFIXMAP_H

#include "swift/Basic/Algorithm.h"
#include "swift/Basic/LLVM.h"
#include "swift/Basic/type_traits.h"
#include "llvm/ADT/ArrayRef.h"
#include "llvm/ADT/PointerIntPair.h"
#include "llvm/Support/raw_ostream.h"
#include <algorithm>
#include <iterator>

namespace swift {

void printOpaquePrefixMap(raw_ostream &out, void *root,
                          void (*printNode)(raw_ostream &, void*));
template <class KeyElementType> class PrefixMapKeyPrinter;

/// A map whose keys are sequences of comparable values, optimized for
/// finding a mapped value for the longest matching initial subsequence.
template <class KeyElementType, class ValueType,
          size_t InlineKeyCapacity
             = max<size_t>((sizeof(void*) - 1) / sizeof(KeyElementType), 1)>
class PrefixMap {
public:
  using KeyType = ArrayRef<KeyElementType>;

  static_assert(IsTriviallyCopyable<KeyElementType>::value,
                "key element type must be trivially copyable");
  static_assert(IsTriviallyConstructible<KeyElementType>::value,
                "key element type must be trivially default-initializable");

private:
  template <typename T>
  union UninitializedStorage {
    alignas(T) char Storage[sizeof(T)];

    template <typename... A>
    void emplace(A && ...value) {
      ::new((void*) &Storage) T(std::forward<A>(value)...);
    }

    T &get() { return *reinterpret_cast<T*>(Storage); }
    const T &get() const { return *reinterpret_cast<T*>(Storage); }
  };

  // We expect to see a lot of entries for keys like:
  //   ab
  //   abcdef
  //   abcdefg
  //   abcdefh
  // corresponding to closely-related paths and different prefixes
  // of the same path.  This basically demands something like a trie.
  //
  // The rules of our data structure are:
  //   - A node's complete key is the concatenation of its non-local prefix
  //     and its local key.  The non-local prefix is the concatenation of
  //     of the local keys of the Further links followed from the root.
  //   - A node's local key contains no common prefix with the local keys of
  //     its left or right siblings.

  struct Node;
  struct NodeBase {
    // The initial layout of this struct is assumed in the out-of-line
    // printing code; you'll need to modify it.

    // Left and right siblings: nodes which share the same non-local
    // prefix as this one, but which share no common local prefix with it.
    Node *Left = nullptr;
    Node *Right = nullptr;

    // Further children: nodes whose non-local prefix is the concatenation
    // of the non-local prefix of this node and its local key.
    Node *Further = nullptr;

    KeyElementType Key[InlineKeyCapacity];
    unsigned char KeyLength : 7;
    unsigned char HasValue : 1;
    static_assert(InlineKeyCapacity < (1 << 7),
                  "can't store inline key length in bit-field");

    NodeBase() : KeyLength(0), HasValue(false) {}

    KeyType getLocalKey() const { return { Key, KeyLength }; }
  };
  struct Node : NodeBase {
  private:
    UninitializedStorage<ValueType> Value;

  public:
    Node() { /* leave Value uninitialized */ }

    // We split NodeBase out so that we can just delegate to something that
    // copies all the other fields.
    Node(const Node &other) : NodeBase(other) {
      if (this->HasValue) {
        Value.emplace(other.Value.get());
      }
    }

    ValueType &get() {
      assert(this->HasValue);
      return Value.get();
    }
    const ValueType &get() const {
      assert(this->HasValue);
      return Value.get();
    }

    template <typename... A>
    void emplace(A && ...value) {
      assert(!this->HasValue);
      Value.emplace(std::forward<A>(value)...);
      this->HasValue = true;
    }
  };

  /// Splits a node in two.  The second part must always be non-empty.
  ///
  ///   ref -> cur 'abcdef' -> ...
  /// =>
  ///   ref -> split 'abc' -> cur 'def' -> ...
  ///
  /// Returns the node that stores the common prefix as its key.
  ///
  /// TODO: consider just reorganizing cur and its Further node if
  /// cur doesn't have a value or left/right children, e.g.
  ///   ref -> cur 'abcdefg' -> further 'hij'
  /// =>
  ///   ref -> cur 'abc' -> further 'defghij'
  static Node *splitNode(Node **ref, size_t splitIndex) {
    auto cur = *ref;
    assert(splitIndex < cur->KeyLength &&
           "split index would leave second node with empty key");

    auto split = new Node();
    split->Further = cur;

    // Move the sibling links of cur onto split unless we're giving split
    // an empty local key, which is the only case where the siblings will
    // have split's key as a prefix.
    if (splitIndex != 0) {
      split->Left = cur->Left;
      split->Right = cur->Right;
      cur->Left = nullptr;
      cur->Right = nullptr;
    }

    // Initialize the key of the split node.
    split->KeyLength = splitIndex;
    memcpy(split->Key, cur->Key, splitIndex * sizeof(KeyElementType));

    // Slide cur's key if the split point wasn't the start.
    if (splitIndex != 0) {
      cur->KeyLength -= splitIndex;
      memmove(cur->Key, cur->Key + splitIndex,
              cur->KeyLength * sizeof(KeyElementType));
    }

    *ref = split;
    return split;
  }

  /// Try to find a node corresponding to a prefix of the given key.
  ///
  /// If 'remainingLookupKey' is non-null, the returned node will correspond
  /// to the longest prefix that had a value set, and 'remainingLookupKey'
  /// will be set to the part of the key that was not matched.  The tree
  /// will not be modified.
  ///
  /// If 'remainingLookupKey' is null, the returned node will correspond
  /// to the complete lookup key.  This node will be created if necessary.
  Node *getOrCreatePrefixNode(KeyType lookupKey,
                              KeyType *remainingLookupKey) {
    // Invariant: 'best' contains the last node we followed the Further
    // link of that had a value.  This is used only when not creating
    // an exact match.
    Node *best = nullptr;

    Node **next = &Root;
    while (Node * const cur = *next) {
      KeyType curKey = cur->getLocalKey();

      // Compare the lookup key with the stored key in the node.
      size_t len = std::min(curKey.size(), lookupKey.size());
      size_t i = 0;
      for (; i != len; ++i) {
         if (lookupKey[i] != curKey[i]) break;
      }

      // If we didn't reach the end of the common length, then we have two
      // basic cases:
      //    looking up 'def' in 'abc' or 'ghi'
      //    looking up 'abd' in 'abc' or 'abce'
      if (i != len) {
        assert(len != 0);
        bool goLeft = (lookupKey[i] < curKey[i]);

        // If there's no common prefix, just go to the appropriate side.
        if (i == 0) {
          next = (goLeft ? &cur->Left : &cur->Right);
          continue;
        }

        // Otherwise, there's a common prefix, but it's not cur's entire
        // key, so there's no node at that common prefix.  That means that
        // there can't be an exact match.  So if we don't need to return
        // one, we can just stop here.
        if (remainingLookupKey)
          return best;

        // Otherwise, we need to split cur at the appropriate place.
        Node *split = splitNode(next, i);

        // Continue from a sibling of its Further link.
        lookupKey = lookupKey.slice(i);
        next = (goLeft ? &split->Further->Left : &split->Further->Right);
        assert(*next == nullptr);
        break;
      }

      // If we did reach the end of the common length, then we have three
      // cases:
      //   looking up 'abc' in 'abc'
      //   looking up 'abc' in 'abcdef'
      //   looking up 'abc' in 'ab'

      // We might have exhausted the node's local key.
      // (This could be empty.)
      if (len == curKey.size()) {
        lookupKey = lookupKey.slice(len);

        // Remember this as the best mapped match if it has a value.
        if (remainingLookupKey && cur->HasValue) {
          best = cur;
          *remainingLookupKey = lookupKey;
        }

        // If we've exhausted the lookup key, too, we have an exact match.
        if (lookupKey.empty()) {
          return (remainingLookupKey ? best : cur);
        }

        // Otherwise, we have a suffix match; continue along the Further
        // path.
        next = &cur->Further;
        continue;
      }

      // Otherwise, we matched a prefix of the node's key.
      assert(lookupKey.size() < curKey.size());

      // If we don't need to create an exact node, don't claim anything
      // more from the key and just use our deepest match.
      if (remainingLookupKey) {
        return best;
      }

      // Okay, we're supposed to return a node that exactly matches the key.
      // Split 'cur'.
      Node *split = splitNode(next, len);
      return split;
    }

    // Okay, we reached the end of our search.  If we don't need an exact
    // match, return our best match so far.
    if (remainingLookupKey) {
      return best;
    }

    // Otherwise, create nodes until we're out of lookup key.
    // TODO: balance the subtree when creating nodes to the left or right.
    do {
      best = new Node();
      *next = best;
      next = &best->Further;

      auto len = std::min(InlineKeyCapacity, lookupKey.size());
      best->KeyLength = len;
      memcpy(best->Key, lookupKey.data(), len * sizeof(KeyElementType));
      lookupKey = lookupKey.slice(len);
    } while (!lookupKey.empty());

    return best;
  }

  /// Delete all the nodes in a subtree.
  static void deleteTree(Node *root) {
    if (!root) return;

    SmallVector<Node *, 8> stack;
    auto pushChildrenAndDelete = [&](Node *node) {
      if (node->Left) stack.push_back(node->Left);
      if (node->Right) stack.push_back(node->Right);
      if (node->Further) stack.push_back(node->Further);
      delete node;
    };
    pushChildrenAndDelete(root);
    while (!stack.empty()) {
      pushChildrenAndDelete(stack.pop_back_val());
    }
  }

  /// Copy all the nodes in a subtree.
  static Node *cloneTree(Node *root) {
    if (!root) return nullptr;

    SmallVector<Node **, 8> stack;
    auto copyAndPushChildren = [&](Node **ptr) {
      assert(*ptr);
      Node *copy = new Node(**ptr);
      *ptr = copy;
      if (copy->Left) stack.push_back(&copy->Left);
      if (copy->Right) stack.push_back(&copy->Right);
      if (copy->Further) stack.push_back(&copy->Further);
    };
    copyAndEnqueueChildren(&root);
    while (!stack.empty()) {
      copyAndEnqueueChildren(stack.pop_back_val());
    }
    return root;
  }

  Node *Root = nullptr;

public:
  PrefixMap() {}

  PrefixMap(const PrefixMap &other) : Root(cloneTree(other.Root)) {}
  PrefixMap(PrefixMap &&other) : Root(other.Root) {
    other.Root = nullptr;
  }
  PrefixMap &operator=(const PrefixMap &other) {
    deleteTree(Root);
    Root = cloneTree(other.Root);
    return *this;
  }
  PrefixMap &operator=(PrefixMap &&other) {
    deleteTree(Root);
    Root = other.Root;
    other.Root = nullptr;
    return *this;
  }

  ~PrefixMap() {
    deleteTree(Root);
  }

  /// Are there any entries in this map?
  bool empty() const {
    // The only way to create nodes is to insert an entry, and we don't
    // yet support delete, so having any nodes means we're non-empty.
    return Root == nullptr;
  }

  /// Return the number of entries in this map.
  size_t size() const {
    if (!Root) return 0;

    size_t result = 0;
    SmallVector<Node *, 16> stack;
    auto handleNode = [&](Node *node) {
      if (node->HasValue) result++;
      if (node->Left) stack.push_back(node->Left);
      if (node->Right) stack.push_back(node->Right);
      if (node->Further) stack.push_back(node->Further);
    };
    handleNode(Root);
    while (!stack.empty())
      handleNode(stack.pop_back_val());
    return result;
  }

  /// An input iterator over the entries in the map.
  ///
  /// This iterator stores a stack of the access path to the entry and
  /// is therefore expensive to copy, and its operator* returns a proxy
  /// object with a reference to its internal storage.  These are both
  /// legal for C++ input iterators, but still, be careful.
  class const_iterator {
  protected:
    enum Position {
      /// We are visiting the node's left subtree.
      Left,
      /// If the node is on the top of the stack, we are visiting its value.
      /// Otherwise, we are visiting its further subtree.
      Further,
      // We remove the node from the stack when visiting its right subtree.
    };
    using NodeAndPosition = llvm::PointerIntPair<Node*, 1, Position>;
    SmallVector<NodeAndPosition, 8> Stack;
  public:
    const_iterator() {}
    explicit const_iterator(Node *node) { enter(node); }

    /// A proxy object referencing a valid entry in the map.
    class ConstEntryProxy {
      ArrayRef<NodeAndPosition> Path;
    public:
      explicit ConstEntryProxy(ArrayRef<NodeAndPosition> path) : Path(path) {
        assert(!Path.empty() && Path.back().getPointer()->HasValue);
      }

      /// Return the value of the entry.  The returned reference is valid
      /// as long as the entry remains in the map.
      const ValueType &getValue() const {
        return Path.back().getPointer()->get();
      }

      /// Read the value's key into the given buffer.
      KeyType getKey(SmallVectorImpl<KeyElementType> &buffer) const {
        buffer.clear();
        for (auto &entry : Path.drop_back()) {
          if (entry.getInt() != Further) continue;
          auto key = entry.getPointer()->getLocalKey();
          buffer.append(key.begin(), key.end());
        }
        auto key = Path.back().getPointer()->getLocalKey();
        buffer.append(key.begin(), key.end());
        return buffer;
      }
    };

    /// Return a proxy value for the entry.  The returned proxy is invalidated
    /// by any change to the underlying iterator.
    ConstEntryProxy operator*() const {
      assert(!Stack.empty());
      assert(Stack.back().getPointer()->HasValue);
      return ConstEntryProxy(Stack);
    }

    /// Advance the iterator.
    const_iterator &operator++() {
      assert(!Stack.empty());

      while (true) {
        if (Stack.back().getInt() == Left) {
          Stack.back().setInt(Further);
          if (Stack.back().getPointer()->HasValue) return *this;
        }
        if (enter(Stack.back().getPointer()->Further)) return *this;

        do {
          Node *top = Stack.pop_back_val().getPointer();
          if (enter(top->Right)) return *this;
          if (Stack.empty()) return *this;
        } while (Stack.back().getInt() == Further);
      }
    }
    const_iterator operator++(int) {
      const_iterator copy = *this;
      operator++();
      return copy;
    }

    bool operator==(const const_iterator &other) const {
      return Stack == other.Stack;
    }
    bool operator!=(const const_iterator &other) const {
      return !operator==(other);
    }

    using difference_type = ptrdiff_t;
    using iterator_category = std::input_iterator_tag;
    using value_type = ConstEntryProxy;
    using pointer = ConstEntryProxy;
    using reference = ConstEntryProxy;

  private:
    bool enter(Node *node) {
      if (!node) return false;
      Stack.push_back({node, Left});
      if (enter(node->Left)) return true;
      Stack.back().setInt(Further);
      if (node->HasValue) return true;
      if (enter(node->Further)) return true;
      Stack.pop_back();
      return enter(node->Right);
    }
  };

  /// An input iterator over the entries in this map.
  ///
  /// This iterator stores a stack of the access path to the entry and
  /// is therefore expensive to copy, and its operator* returns a proxy
  /// object with a reference to its internal storage.  These are both
  /// legal for C++ input iterators, but still, be careful.
  struct iterator : const_iterator {
    iterator() : const_iterator() {}
    explicit iterator(Node *node) : const_iterator(node) {}

    struct EntryProxy : const_iterator::ConstEntryProxy {
      explicit EntryProxy(
                       ArrayRef<typename const_iterator::NodeAndPosition> path)
        : const_iterator::ConstEntryProxy(path) {}
      ValueType &getValue() const {
        return const_cast<ValueType &>(
                                  const_iterator::ConstEntryProxy::getValue());
      }
    };

    EntryProxy operator*() const {
      return EntryProxy(this->Stack);
    }

    iterator &operator++() {
      return static_cast<iterator&>(const_iterator::operator++());
    }
    iterator operator++(int) {
      iterator copy = *this;
      operator++();
      return copy;
    }

    // Base implementations of operator== are fine.

    using value_type = EntryProxy;
    using pointer = EntryProxy;
    using reference = EntryProxy;
  };

  iterator begin() { return iterator(Root); }
  iterator end() { return iterator(); }

  const_iterator begin() const { return const_iterator(Root); }
  const_iterator end() const { return const_iterator(); }

  /// A handle to the mapping for a given key.  Only invalidated by
  /// changes that remove the mapping.
  class Handle {
    Node *Ptr;
  public:
    Handle() : Ptr(nullptr) {}
    explicit Handle(Node *ptr) : Ptr(ptr) {}

    explicit operator bool() const { return Ptr != nullptr; }
    ValueType &operator*() const {
      return Ptr->get();
    }
  };

  using KeyIterator = typename KeyType::iterator;

  /// Find the longest prefix of the given encoded sequence which has
  /// an entry in this map, and return an iterator corresponding to the
  /// end of the prefix.
  std::pair<Handle, KeyIterator>
  findPrefix(KeyType key) const {
    KeyType remainingKey;
    auto node = const_cast<PrefixMap*>(this)
                             ->getOrCreatePrefixNode(key, &remainingKey);
    assert(!node || node->HasValue);
    return { Handle(node), remainingKey.begin() };
  }

  /// Remove all entries in the map.
  void clear() {
    deleteTree(Root);
    Root = nullptr;
  }

  /// Get or create an entry in the map.
  ///
  /// \return a handle to the entry and a bool indicating (if true)
  ///   that the map was modified to insert the mapping.
  template <typename Fn>
  std::pair<Handle, bool>
  insertLazy(KeyType key, const Fn &create) {
    auto node = getOrCreatePrefixNode(key, nullptr);
    assert(node);
    if (node->HasValue) {
      return { Handle(node), false };
    } else {
      node->emplace(create());
      return { Handle(node), true };
    }
  }

  std::pair<Handle, bool>
  insert(KeyType key, ValueType &&value) {
    return insertLazy(key,
                      [&]() -> ValueType && { return std::move(value); });
  }

  std::pair<Handle, bool>
  insert(KeyType key, const ValueType &value) {
    return insertLazy(key,
                      [&]() -> const ValueType & { return value; });
  }

  /// Insert a new entry into the map, asserting that it doesn't
  /// already exist.
  template <typename Fn>
  Handle insertNewLazy(KeyType key, const Fn &create) {
    auto node = getOrCreatePrefixNode(key, nullptr);
    assert(node);
    node->emplace(create());
    return Handle(node);
  }

  Handle insertNew(KeyType key, ValueType &&value) {
    return insertNewLazy(key,
                         [&]() -> ValueType && { return std::move(value); });
  }

  Handle insertNew(KeyType key, const ValueType &value) {
    return insertNewLazy(key,
                         [&]() -> const ValueType & { return value; });
  }

  void dump() const { print(llvm::errs()); }
  void print(raw_ostream &out) const {
    printOpaquePrefixMap(out, Root,
                         [](raw_ostream &out, void *_node) {
      Node *node = reinterpret_cast<Node*>(_node);
      PrefixMapKeyPrinter<KeyElementType>::print(out, node->getLocalKey());
      if (node->HasValue) {
        out << " (" << node->get() << ')';
      }
    });
  }
};

/// The standard implementation of a key printer:
///   {0,1,2,3}
template <class KeyElementType>
class PrefixMapKeyPrinter {
public:
  static void print(raw_ostream &out, ArrayRef<KeyElementType> key) {
    out << '{';
    for (size_t i = 0; i != key.size(); ++i) {
      if (i != 0) out << ',';
      out << key[i];
    }
    out << '}';
  }
};

/// A key printer for char sequences that prints as a quoted string:
///   "hello, \"world\""
template <>
class PrefixMapKeyPrinter<char> {
public:
  static void print(raw_ostream &out, ArrayRef<char> key);
};

/// A key printer for byte sequences that prints as a byte-string:
//   '0F346E'
template <>
class PrefixMapKeyPrinter<unsigned char> {
public:
  static void print(raw_ostream &out, ArrayRef<unsigned char> key);
};

} // end namespace swift

#endif // SWIFT_BASIC_PREFIXMAP_H