fuchsia / third_party / rust-crates / 07cbccdb4f89c8cea98e22273c8550436ef7dc04 / . / rustc_deps / vendor / rand-0.5.6 / examples / monty-hall.rs

// Copyright 2013-2018 The Rust Project Developers. See the COPYRIGHT | |

// file at the top-level directory of this distribution and at | |

// https://rust-lang.org/COPYRIGHT. | |

// | |

// Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or | |

// https://www.apache.org/licenses/LICENSE-2.0> or the MIT license | |

// <LICENSE-MIT or https://opensource.org/licenses/MIT>, at your | |

// option. This file may not be copied, modified, or distributed | |

// except according to those terms. | |

//! ## Monty Hall Problem | |

//! | |

//! This is a simulation of the [Monty Hall Problem][]: | |

//! | |

//! > Suppose you're on a game show, and you're given the choice of three doors: | |

//! > Behind one door is a car; behind the others, goats. You pick a door, say | |

//! > No. 1, and the host, who knows what's behind the doors, opens another | |

//! > door, say No. 3, which has a goat. He then says to you, "Do you want to | |

//! > pick door No. 2?" Is it to your advantage to switch your choice? | |

//! | |

//! The rather unintuitive answer is that you will have a 2/3 chance of winning | |

//! if you switch and a 1/3 chance of winning if you don't, so it's better to | |

//! switch. | |

//! | |

//! This program will simulate the game show and with large enough simulation | |

//! steps it will indeed confirm that it is better to switch. | |

//! | |

//! [Monty Hall Problem]: https://en.wikipedia.org/wiki/Monty_Hall_problem | |

#![cfg(feature="std")] | |

extern crate rand; | |

use rand::Rng; | |

use rand::distributions::{Distribution, Uniform}; | |

struct SimulationResult { | |

win: bool, | |

switch: bool, | |

} | |

// Run a single simulation of the Monty Hall problem. | |

fn simulate<R: Rng>(random_door: &Uniform<u32>, rng: &mut R) | |

-> SimulationResult { | |

let car = random_door.sample(rng); | |

// This is our initial choice | |

let mut choice = random_door.sample(rng); | |

// The game host opens a door | |

let open = game_host_open(car, choice, rng); | |

// Shall we switch? | |

let switch = rng.gen(); | |

if switch { | |

choice = switch_door(choice, open); | |

} | |

SimulationResult { win: choice == car, switch } | |

} | |

// Returns the door the game host opens given our choice and knowledge of | |

// where the car is. The game host will never open the door with the car. | |

fn game_host_open<R: Rng>(car: u32, choice: u32, rng: &mut R) -> u32 { | |

let choices = free_doors(&[car, choice]); | |

rand::seq::sample_slice(rng, &choices, 1)[0] | |

} | |

// Returns the door we switch to, given our current choice and | |

// the open door. There will only be one valid door. | |

fn switch_door(choice: u32, open: u32) -> u32 { | |

free_doors(&[choice, open])[0] | |

} | |

fn free_doors(blocked: &[u32]) -> Vec<u32> { | |

(0..3).filter(|x| !blocked.contains(x)).collect() | |

} | |

fn main() { | |

// The estimation will be more accurate with more simulations | |

let num_simulations = 10000; | |

let mut rng = rand::thread_rng(); | |

let random_door = Uniform::new(0u32, 3); | |

let (mut switch_wins, mut switch_losses) = (0, 0); | |

let (mut keep_wins, mut keep_losses) = (0, 0); | |

println!("Running {} simulations...", num_simulations); | |

for _ in 0..num_simulations { | |

let result = simulate(&random_door, &mut rng); | |

match (result.win, result.switch) { | |

(true, true) => switch_wins += 1, | |

(true, false) => keep_wins += 1, | |

(false, true) => switch_losses += 1, | |

(false, false) => keep_losses += 1, | |

} | |

} | |

let total_switches = switch_wins + switch_losses; | |

let total_keeps = keep_wins + keep_losses; | |

println!("Switched door {} times with {} wins and {} losses", | |

total_switches, switch_wins, switch_losses); | |

println!("Kept our choice {} times with {} wins and {} losses", | |

total_keeps, keep_wins, keep_losses); | |

// With a large number of simulations, the values should converge to | |

// 0.667 and 0.333 respectively. | |

println!("Estimated chance to win if we switch: {}", | |

switch_wins as f32 / total_switches as f32); | |

println!("Estimated chance to win if we don't: {}", | |

keep_wins as f32 / total_keeps as f32); | |

} |