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; Test that an INT followed by an IRET are decoded correctly.
;
; Variant: no cpl filtering
;
;
;           Software interrupts receive FUP(CLIP) + TIP(BLIP?)
;
;           We can not reliably determine whether the FUP/TIP belongs to the
;           software interrupt or to an asynchronous interrupt that was taken
;           before the instruction.
;
;           To distinguish the two cases we would need to read ahead but that
;           may require decoding an unknown amount of code (in the kernel or
;           hypervisor or even in different processes) until we return either
;           to CLIP if it was an asynchronous interrupt or to NLIP (or even to
;           a later IP) if it wasn't.
;
;           Instead, we assume that it was an asynchronous interrupt.  Control
;           appears to flow from before the software interrupt instruction to
;           the interrupt handler and back after the instruction.
;
;           This is wrong most of the time.  But it is predictably wrong and it
;           avoids the case where we incorrectly assume a synchronous transfer
;           and get out of sync.
;

org 0x100000
bits 64
; @pt p1: psb()
; @pt p2: fup(3: %l0)
; @pt p3: mode.exec(64bit)
; @pt p4: psbend()
l0: nop

; @pt p5: fup(1: %l1)
; @pt p6: tip(3: %l5)

l1: int 42
l2: nop
l3: nop
l4: hlt

l5: nop
l6: iret
l7: hlt

; @pt p7: tip(3: %l2)

; @pt p8: fup(1: %l3)
; @pt p9: tip.pgd(0: %l4)


; @pt .exp(ptdump)
;%0p1  psb
;%0p2  fup        3: %0l0
;%0p3  mode.exec  cs.l
;%0p4  psbend
;%0p5  fup        1: %?l1.2
;%0p6  tip        3: %0l5
;%0p7  tip        3: %0l2
;%0p8  fup        1: %?l3.2
;%0p9  tip.pgd    0: %?l4.0

; @pt .exp(ptxed)
;%0l0 # nop
;[interrupt] # this should really be:  l1: int 42
;%0l5 # nop
;%0l6 # iret
;%0l2 # nop
;[disabled]